Matter waves – wave-particle duality/ Dual nature of matter waves

 Matter waves – wave-particle duality/ Dual nature of matter waves

We know that a particle can occupy a certain amount of space and contain some 

quantity of mass. If its position is changing continuously then it should gain some velocity 

(v), momentum (p), acceleration (a) and energy (E). So a particle can be characterized by its 

  • (i) mass 
  • (ii) velocity 
  • (iii) momentum 
  • (iv) energy. 

Similarly, a wave can be characterized by its (i) amplitude (ii) frequency 

(iii) wavelength (iv) period (v) phase (vi) wave velocity.

From the above analysis, it can be concluded that both particle and wave should not 

contain similar characteristics. But from successful experiments like the photoelectric effect, 

Crompton effect, photons are moving like particles. And from other experiments like x-ray 

diffraction, these x-rays are moving like waves. So from this analysis, it can be concluded 

that both particles and waves should have contained dual nature. It is known as the dual nature of 

matter-wave and is proposed by de Broglie.

de Broglie’s hypothesis or deBroglie wavelength of a particle

According to de Broglie’s dual nature of matter-wave, the matter-wave should 

exhibit wave nature as well as particle nature. The waves associated with matter are known as 

matter waves.

From Planck’s theory of radiation, consider a photon of mass ‘m’, moving with a 

velocity ‘v’ and frequency ‘γ’ then the energy of a photon is written as 

𝐸 = ℎ 𝛾.                                                           (1)

from Einstein’s mass-energy relation,

𝐸 = 𝑚 𝑐`2                                                       (2)

(1) = (2), ℎ 𝛾 = 𝑚 𝑐`2.                                   (3)

We know 𝑣 = 𝛾 𝜆

let v = c then 𝑐 = 𝛾` 𝜆

𝛾 =c/𝜆

(4) in (3), ℎ c/𝜆=mc`2

𝜆 =ℎ/𝑚𝑐

let c = v, 𝜆 =ℎ/𝑚𝑣.                                            (5)

momentum = p = m v                                   (6)

(6) in (5), 𝜆 =ℎ/𝑝.                                             (7)

Due to the motion of the particle, it gains kinetic energy (E)

Kinetic energy = E = 1/2 𝑚 𝑣`2

𝐸 =𝑚`2𝑣`2/2𝑚=(𝑚𝑣)`2/2𝑚=𝑝`2/2𝑚

𝑝`2 = 2𝑚𝐸

𝑝 = √2𝑚𝐸 (8)

(8) in (7) 𝜆 =ℎ/√2𝑚𝐸                                      (9)

where      h = Planck’s constant

                 m = mass of particle/photons

                  E = kinetic energy of the particle

       de Broglie wavelength of an electron

Getting Info...

Post a Comment

Cookie Consent
We serve cookies on this site to analyze traffic, remember your preferences, and optimize your experience.
It seems there is something wrong with your internet connection. Please connect to the internet and start browsing again.
AdBlock Detected!
We have detected that you are using adblocking plugin in your browser.
The revenue we earn by the advertisements is used to manage this website, we request you to whitelist our website in your adblocking plugin.
Contact Us